Quant Test for NIACL AO Prelims Exam Set – 12

Directions(1-5): Find the missing term ‘?’ of the following series.

1. 8,13,26,51,92,?
   133
   153
   140
   132
   150
   Option B
   +(1^2+2^2)
   +(2^2+3^2)
   +(3^2+4^2)
   +(4^2+5^2)
   +(5^2+6^2)
   ? = 153

    

2. 630,210,84,42,?,28,56
   15
   20
   28
   16
   13
   Option C
   /3
   /2.5
   /2
   /1.5
   /1
   /0.5
   ? = 28

    

3. 463,453,433,403,?,313
   333
   363
   350
   344
   362
   Option B
   -10.-20,-30,-40,-50
   ? = 363

    

4. 24,16,28,74,?,1187.5
   222
   255
   241
   263
   272
   Option D
   *0.5+4
   *1.5+4
   *2.5+4
   *3.5+4
   *4.5+4
   ? = 263

    

5. 23,40,61,86,?,148
   95
   100
   88
   115
   90
   Option D
   +17,+21,+25,+29,+33
   ? = 115

    

6. At what rate of simple interest must Rs.15900 be deposited for 4 years to receive the same interest that is obtained by investing Rs.15000 at 12% per annum compound interest compounded for 2 years ?
   8
   6
   7
   5
   4
   Option B
   Compound interest earned = 15000*{(1+0.12)^2 – 1} = Rs.3816
   Let rate be r%.
   Simple interest earned = 15900*4*r/100 = 3816
   => r = 6

    

7. If the numerator of a fraction is increased by 40% and denominator in increased by 25% then the resultant fraction will become 7/5. What is the original fraction?
   3/5
   11/9
   7/2
   4/3
   5/4
   Option E
   Let the original fraction be x/y. (x*1.4)/(y*1.25) = 7/5
   => x/y = 5/4

    

8. Find the area of the circular field having radius equal to the breadth of a room with area of four walls 840 m^2 and height 10 m if it is given that ratio of length and breadth of the room is 4:3 resp.(Take pi = 3)
   900 m^2
   818 m^2
   919 m^2
   972 m^2
   700 m^2
   Option D
   2(l+b)*h = 840
   => 2(4x+3x)*10 = 840
   => x = 6
   Breadth = 3*6 = 18 m
   Area of the circular field = pi*(18)^2 = 972 m^2

    

9. Present ages of A and B are in the ratio of 2:3 resp. Present ages of C and D are in the ratio of 8:7 resp. Present average age of A ,B and C is 46 years. Present average age of B,C and D is 48 years. Find the difference between the present ages of B and C.
   4 years
   2 years
   5 years
   8 years
   6 years
   Option E
   Let the present ages of A,B,C and D are 2x,3x,8y and 7y resp.
   Now, 2x+3x+8y = 3*46 5x+8y = 138 —-(1)
   Also, 3x+8y+7y = 3*48 —–(2)
   On solving (1) and (2), we get
   x = 18
   y = 6
   Difference between present ages of B and C = 54 – 48 = 6 years

    

10. A cricket team of 11 players is to be selected from a group of 8 batsmen, 5 bowlers and 3 wicketkeepers. In how many ways a team a having at least 4 bowlers and exactly 1 wicketkeeper is selected?
    500
    555
    588
    610
    585
    Option C
    Required number of ways = 3C1*5C4*8C6 + 3C1*5C5*8C5
    = 420+168 = 588